(x+3)(2x^4-3x^2-5)=

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Solution for (x+3)(2x^4-3x^2-5)= equation: 


Simplifying
(x + 3)(2x4 + -3x2 + -5) = 0

Reorder the terms:
(3 + x)(2x4 + -3x2 + -5) = 0

Reorder the terms:
(3 + x)(-5 + -3x2 + 2x4) = 0

Multiply (3 + x) * (-5 + -3x2 + 2x4)
(3(-5 + -3x2 + 2x4) + x(-5 + -3x2 + 2x4)) = 0
((-5 * 3 + -3x2 * 3 + 2x4 * 3) + x(-5 + -3x2 + 2x4)) = 0
((-15 + -9x2 + 6x4) + x(-5 + -3x2 + 2x4)) = 0
(-15 + -9x2 + 6x4 + (-5 * x + -3x2 * x + 2x4 * x)) = 0
(-15 + -9x2 + 6x4 + (-5x + -3x3 + 2x5)) = 0

Reorder the terms:
(-15 + -5x + -9x2 + -3x3 + 6x4 + 2x5) = 0
(-15 + -5x + -9x2 + -3x3 + 6x4 + 2x5) = 0

Solving
-15 + -5x + -9x2 + -3x3 + 6x4 + 2x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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